Math, asked by pguptanes, 11 hours ago

PROVE THAT 3( AB+BC+CA)>2(AD+BE+CF) ,IF AD ,BE AND CF are three medians of triangle ABC .

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Answered by rishvinrishvin21
0

Answer:

In a triangle ABC, median AD, BE and CF intersect at point G. Prove that : 4(AD + BE + CF) > 3(AB + BC + CA)Read more on Sarthaks.com - https://www.sarthaks.com/757941/in-a-triangle-abc-median-ad-be-and-cf-intersect-at-point-g-prove-that-4-ad-be-cf-3-ab-bc-ca

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