Question

Prove that 3 consecutive numbers are divisible by 3

Answer 1

Prove that the sum of three consecutive integers is divisible by 3.

First, let the first integer be k,

the second integer be k + 1, and the third integer be k + 2.

Thus, we have three consecutive integers.

The sum of these three integers is k + (k + 1) + (k + 2) = 3k + 3 = 3(k + 1).