prove that (3 - cot30) = tan²60 - 2sin60
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Answer:
3-cot30=tan^2-2sin60
L.H.S=3-cot30=3-√3R.H.S=tan^60-2si
R.H.S=tan^2 (60)-2sin60
=√3^2-2×√3÷2
=3-√3
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