Prove that √3 es irrational.
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Let √3 be rational number.
=>√3 = p/q
p/q are integers and have no common factor and q is not equal to 0.
3 = p²/q²
=>3 = p²/q×q
=>3q = p²/q
Case I:
when q = 1
3×1 = p²/1
3 = p²
There is no integer whose square is 3.
So, this case is not possible.
Case II:
When q is not equal to 1.
3q = p²/q
=>Integer is not equal to non integer.
√3 is not a rational number
Thus, it is an irrational number.
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