prove that√3 is a irrational number
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Let, √3 be a rational number.
So, √3=p/q,
where; p≠0 and p and q are
co-prime numbers.
or p=√3q
On squaring both sides:
p²=3q²
» 3 divides p² and p
So, we can write that:
p=3x....(1)
Now, as p²=3q²
» p²=3q²=(3x)²
» 3q²=9x²
or q²=3x²
» 3 divides q² and q
But, p and q must be co prime number so as for √3 to be a rational.
This contradiction is due to our wrong assumption, that √3 is rational.
Hence, √3 is proved to be irrational.
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