Question

prove that √3 is a irrational number​

Answer 1

Answer:

to prove : /√3 is irrational

proof : let √3 be a rational no. and a and b be co prime numbers

so √3=a/b

, b√3 = a

squaring both sides

$3b ^2 = a ^{2}$

$so \:$

now let a = 3c

so

$a ^{2} = 9c^{2}$

so 3b^2 = 9c^2

b^2 = 3c^2

so our contradiction is wrong which we had taken √3 is rational

since √3 is irrational