prove that √3 is a irrational number
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Since both q and r are odd, we can write q=2m−1 and r=2n−1 for some m,n∈N. ... Therefore there exists no rational number r such that r2=3. Hence the root of 3 is an irrational number..
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it is irrational no because it is not a fraction and it is a square root
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