prove that √3 is an irrational number
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let √3 as rational no.
then √3 can be written as
√3=a/b
squaring both side
(√3)2 = (a/b)2
3b2 = a2
hence 3 divides b2 as well a2
so √3 must not be rational no.
this proves √3 is a irrational no.
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