Prove that √3 is an irrational number
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Let √3 be a rational number.
Then √3 = q/p ( Assumed )
Squaring both sides --
(√3)² = (q/p)²
3 = p²/ q²
Therefore
3q² = p²
3 divides p² » 3 divides p
Therefore 3 is a factor of p
Now Taking p = 3c
Again 3q² = (3c)²
3q² = 9c²
3 divides q²» 3 divides q
3 is a factor of q
Therefore 3 is a common factor of p and q It is a contradiction to our assumption that q/p is rational.
Hence √3 is an irrational number.
Hope it helps you ✌
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