Prove that √3 is an irrational number.
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Question :- Prove that √3 is an irrational number.
Solution:
Let to be √3 be Rational number
Let it's simplest form be a/b
then,
Here,
Note:-
a and b are Integer having no common factor other than 1.
Again,
√3=a/b
Now,
Squaring the both sides means (L.H.S and RHS)
we get,
(√3)²=(a/b)²
(3)=a²/b²
Here, using cross multiplication...
3b²=a²
Now,.
3 Divide a²
Again,
3 Divide a
Note Reason:- 3 is a prime Number and 3 Divide by a²
Now,
Let to be a=3c
then,
(3b²)=9c²
Note:- 9 divide by 3
b²=3c²
Again,
3 Divide by b²
3 Divide by a
Now,
3 is a common factor of a and b...
Thus,
√3 is an irrational number..
Conclusion :- √3 is an irrational number.
__________________________________
Thanks for the question dear !!
♥♥♥♥
_________________________________
Question :- Prove that √3 is an irrational number.
Solution:
Let to be √3 be Rational number
Let it's simplest form be a/b
then,
Here,
Note:-
a and b are Integer having no common factor other than 1.
Again,
√3=a/b
Now,
Squaring the both sides means (L.H.S and RHS)
we get,
(√3)²=(a/b)²
(3)=a²/b²
Here, using cross multiplication...
3b²=a²
Now,.
3 Divide a²
Again,
3 Divide a
Note Reason:- 3 is a prime Number and 3 Divide by a²
Now,
Let to be a=3c
then,
(3b²)=9c²
Note:- 9 divide by 3
b²=3c²
Again,
3 Divide by b²
3 Divide by a
Now,
3 is a common factor of a and b...
Thus,
√3 is an irrational number..
Conclusion :- √3 is an irrational number.
__________________________________
Thanks for the question dear !!
♥♥♥♥
chiku0:
Thank u so much Di
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