Prove that √3 is an irrational number,Hence show that 5+√3 is also an irrational
Answers
Answered by
23
Solution :
Let us assume , 5 + √3 is rational.
Let 5 + √3 = a/b , where a,b are
integers and b ≠ 0.
√3 = a/b - 5
=> √3 = ( a - 5b )/b
Since , a , b are integers , (a-5b)/b is
rational , and so √3 is rational .
This contradicts the fact that √3 is
irrational .
Hence , 5 + √3 is irrational.
••••••
Let us assume , 5 + √3 is rational.
Let 5 + √3 = a/b , where a,b are
integers and b ≠ 0.
√3 = a/b - 5
=> √3 = ( a - 5b )/b
Since , a , b are integers , (a-5b)/b is
rational , and so √3 is rational .
This contradicts the fact that √3 is
irrational .
Hence , 5 + √3 is irrational.
••••••
Answered by
2
Answer:
Step-by-step explanation:Solution :
Let us assume , 5 + √3 is rational.
Let 5 + √3 = a/b , where a,b are
integers and b ≠ 0.
√3 = a/b - 5
=> √3 = ( a - 5b )/b
Since , a , b are integers , (a-5b)/b is
rational , and so √3 is rational .
This contradicts the fact that √3 is
irrational .
Hence , 5 + √3 is irrational.
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