Prove that √3 is an irrational number. Using it, show that 5 + 2 √3 is not a rational number.
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Let √3 is an rational number so it can be written in the form of p/q where p,q have not common factor.p,q are integer such that q is not equal to 0
√3 = p/q
Squaring both sides, 3=p^2/q^2
3q^2=p^2
It means 3 is a factor of q^2 so it's also a factor of q
(By theorem) 3 will also a factor of p
But it contradict our supposition this implies √3 is an irrational number
5+2√3=p/q
2√3=p/q-5
2√3=p-5q/q
√3=p-5q/2q
p is an integer 5q is an integer 2q is an integer so R.H.S will be integer
But it contradict because we already prove that √3 is an irrational number so 5+2√3 is not a rational number. Hence, it Is proved
Hope it may help you
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