prove that √3 is irrational
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2
Answer:
√3 =1.732 and it is irrational
Answered by
3
Step-by-step explanation:
Let's assume that √3 is rational. i.e
3/√3=m/n3=m/n, where m and n have no common factors.
Multiplying both side by nn and squaring we get.
3n^2==m^2
Since lhs is divisible by 3, rhs should also be divisible by 3. Thus, we can write m as 3p
3n^2=(3p)^2
=> 3n^2=9p^2
=> n2=3p^2
Since rhs is divisible by 3, lhs should also be divisible by 3. Thus nn is divisible by 3.
Both n,mn,m are divisible by 3, contradicting our original assumption that m and n are co-prime.
Thus, 3–√3 is irrational. Hence Proved.
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