prove that √3 is irrational
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let, assume that √3 is a rational (where it is written in the form of p / q where p and q is integers or coprime numbers and q is not equal to zero)
=√3=a/b
=b√3=a
by squaring both the sides
=(b)^2 (√3)^2=(a)^2
=3b^2=a^2______equation 1
therefore ,
3 divides a
3 divides a^2
now,
= √3b=√3c
by squaring both the sides
=(b)^2=(√3)^2 (c)^2
=b^2=9c^2__________equation 2
therefore,
3 divides b
therefore,
from equation 1 and 2 , 3 divides p/q where p/q are coprime numbers this contridicts arises due to our wrong assumption that √3 is a rational number
hence, √3 is irrational number
proved
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