prove that √3 is irrational
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first assume to the contradiction that √3 is rational. so √3 is of the p/q form.
so,√3=p/q.
squaring on both the sides.
3=p^/q^..
3q^=p^.
q^=p^/3
therefore p^ is divisible by 3. so p is also divisible by 3.
so we can write p =
so,√3=p/q.
squaring on both the sides.
3=p^/q^..
3q^=p^.
q^=p^/3
therefore p^ is divisible by 3. so p is also divisible by 3.
so we can write p =
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