prove that √3 is irrational.
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Let us assume to the contrary that √3 is a rational number.
It can be expressed in the form of p/q
where p and q are co-primes and q≠ 0.
⇒ √3 = p/q
⇒ 3 = p²/q² (Squaring on both the sides)
⇒ 3q² = p²______________(1)
It means that 3 divides p² and also 3 divides p because each factor should appear two times for the square to exist.
So we have p = 3r
where r is some integer.
⇒ p² = 9r²__________________(2)
from equation (1) and (2)
⇒ 3q² = 9r²
⇒ q² = 3r²
We have two cases to consider now.
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