Question

prove that √3 is irrational​

Answer 1

Answer:

yes it is irrational

Step-by-step explanation:

because it is not repeating

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Answer 2

$let \: us \: assume \: that \: \sqrt{3} is \: an \: irrational \: number. \\ \sqrt{3} = \frac{a}{b} \\ \sqrt{3} = \frac{a} {b {}^{2} }^{2} \\ 3 {b}^{2} = {a}^{2} \\ 3 \: divides \: {a}^{2} \: 3 \: divides \: a \\ a = 3c \\ {a}^{2} = 9 {c}^{2} \\ 3 {b}^{2} = 9 {c}^{2} \\ {b}^{2} = 3 {c}^{2} \\ 3 \: divides \: {b}^{2} \: 3 \: divides \: b \\ hence \: \sqrt{3} \: is \: an \: irrational \: number \:$