prove that √3 is irrational and 1/√3 is irrational
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Let √3 be a rational number
√3 = a/b (a and b are integers and co-primes and b ≠ 0)
On squaring both the sides, 3 = a²/b²
⟹ 3b² = a²
⟹ a² is divisible by 3
⟹ a is divisible by 3
We can write a = 3c for some integer c.
⟹ a² = 9c²
⟹ 3b² = 9c²
⟹ b² = 3c²
⟹ b² is divisible by 3
⟹ b is divisible by 3
From (i) and (ii), we get 3 as a factor of ‘a’ and ‘b’ which is contradicting the fact that a and b are co-primes.
Hence our assumption that√3 is an rational number is false.
∴ √3 is an irrational number.
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