prove that √3 is irrational number
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Let us assume to the contrary that √3 is a rational number. where p and q are co-primes and q≠ 0. It means that 3 divides p2 and also 3 divides p because each factor should appear two times for the square to exist. ... This demonstrates that √3 is an irrational number.
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Step-by-step explanation:
If possible , let 3 be a rational number and its simplest form be.
The contradiction arises by assuming 3 is a rational.
Hence, 3 is irrational.
If possible, Let (7+23 ) be a rational number.
⟹7−(7+23 ) is a rational.
∴ −23 is a rational.
This contradicts the fact that −23 is an irrational number.
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