prove that √3 is irrational number
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you assume to the contrary that √3 is a rational number. where p and q are co-primes and q≠ 0. It means that 3 divides p2 and also 3 divides p because each factor should appear two times for the square to exist. ... This demonstrates that √3 is an irrational number....
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let √3 is rational no
then , it have no common factor
√3= a/b
squaring both side
3= a²/b²
3b²= à².......१
here a² divides 3
a divides 3 also
let a be 3c
form eq१
3b² = (3c)²
3b² = 9c²
b²= 3c²
here b² divides 3
b divides 3 also
here we get a and b have common factor 3
hence our assumption that √3 is rational is wrong
hence √3 is not rational no
hence √3 is irrational no
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