Question

Prove that √3 is irrational number
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Answer 1

Say √3

is rational. Then √3can be represented as ab

, where a and b have no common factors.

So 3=a2b2

and 3b2=a2. Now a2 must be divisible by 3, but then so must a (fundamental theorem of arithmetic). So we have 3b2=(3k)2 and 3b2=9k2 or even b2=3k2 and now we have a contradiction.

What is the contradiction?

Answer 2

REFER TO THE ATTACHMENT ❤️