Question

prove that 3 minus root 2 is an irrational number​

Answer 1

Answer:

Hii mate :-)

Let 3-√2 be a rational number

such that

3-√2 = a/b ,where a and b are integers and b ≠ zero

therefore,

3 - √2 = a/b

=> -√2 = a/b -3

=> √2 = 3 - (a/b)

=> √2 = (3b-a)/b

therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers,

It means that √2 is rational.

But this contradicts the fact that √2 is irrational.

So, it concludes that 3-√2 is irrational.

hence proved..

HOPE IT HELPS,

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Answer 2

Answer:

as we know that A rational number is a number that can be express as the ratio of two integers. A number that cannot be expressed that way is irrational.

3-√2=(p/q)

-√2=(p/q)-3

-√2=p-3q/q

irrigation=rational

therefore, 3-√2 is an irrigation number.

hope it helps you mate

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