prove that 3 minus\sqrt{2} ...{ 3-\sqrt{2} } is irrational....
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To prove that 3+root2 is an irrational number
lets take the opposite i.e 3+root2 is a rational number
hence 3+root2 can be written in the form a/b
hence 3+root2 = a/b
root2 = 1/3 x a/b
root2 = a/3b
here a/3b is rational and root2 is irrational
as irrational cannot be equal to rational
3+root2 is irrational
hoped it helped you
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lets take the opposite i.e 3+root2 is a rational number
hence 3+root2 can be written in the form a/b
hence 3+root2 = a/b
root2 = 1/3 x a/b
root2 = a/3b
here a/3b is rational and root2 is irrational
as irrational cannot be equal to rational
3+root2 is irrational
hoped it helped you
Read more on Brainly.in - https://brainly.in/question/2157279#readmore
PoojaNair:
not 3+root 2...i asked abt 3 - root 2
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0
here it can't we proven it is good question
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