Prove that 3 + quare root of 5 is irrtional
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3+ 25 =28 and it is irritinoal as it is not square of any no.
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Step-by-step explanation:
Let us assume that 3+ √5 is a rational number.
Now,
3+ √5 = a/b
[Here a and b are co-prime numbers]
√5 =[(a/b) -3]
√5 =[( a−3b/b )]
Here, [(a−3b/b) ] is a rational number.
But we know that
√5 is an irrational number.
So, [(a−3b /b )] is also a irrational number.
So, our assumption is wrong.
3+ √5 is an irrational number.
Hence proved.
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