prove that 3 - root 2 is irrational
Answers
Answered by
1
Step-by-step explanation:
3√2is a rational number but this contradicts that √2is irrational number therefore our assumpition hense 3√2 is irrational number
Answered by
8
ANSWER:
- 3-√2 is an Irrational number.
GIVEN:
- Number = 3-√2
TO PROVE:
- 3-√2 is an Irrational number.
SOLUTION:
Let 3-√2 be a rational number which can be expressed in the form of p/q where p and q have no other common factor than 1.
=> 3-√2 = p/q
=> 3-p/q = √2
=> (3q-p)/q = √2
Here:
- (3q-p)/q is rational but √2 is Irrational.
- Thus our contradiction is wrong.
- 3-√2 is an Irrational number.
NOTE:
- This method of proving an irrational number is called contradiction method.
- In this method we first contradict a fact then we prove that our superposition was wrong.
- In this way we can prove that 3-√2 is an Irrational number.
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