Question

Prove that 3+root 2 is irrational number.

Answer 1

Answer:

The Brainliest Answer! 3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. But this contradicts the fact that √2 is irrational..

Answer 2

Answer:

Yes 3+√2 is irrational

Step-by-step explanation:

Let us assume that 3+√2 is a rational

So

3+√2=p\q

√2=p\q-3(transposing 3to RHS)

√2=p\q-3\q(equalising denominator)

So , p\q-3\q

Is a rational number

So, √2 is also a rational number

This contradicte the fact that√2 is irrational

So, 3+√2 is a irrational number

Proved