Question

Prove that 3 root 3 is irrational​

Answer 1

Answer:

as we know that √3 is a irrational number..

so we can assume 3√3 as rational no.

therefore we can write it in the form of a/b

now, 3√3=a/b

√3= a/b/3

and as we know that√3 is an irrational no. so a/b/3 will also be an irrational no...

Answer 2

Answer:

Yep

Step-by-step explanation:

Let us assume 3-√3 is rational

let 3-√3 = a/b (a,b are any integers)

=> 3 - a/b = √3

=> √3 = 3 - a/b

=> √3 = 3b-a/b

For any two integers, RHS (3b-a/b) is rational

But, LHS(√3) is irrational

A rational and irrational are never equal

So, our assumption is false

Therefore, 3-√3 is irrational

Hope it hlp