Math, asked by NamgayWangchuk177, 1 month ago

prove that 3 - root 3 whole square is irrational

Answers

Answered by py3705880
0

Answer:

RHS is rational while the LHS is irrational. This is not possible and therefore contradicts our assumption that (root 3 + root 5)2 is rational. Therefore (root 3 + root 5)2 is irrational.

Answered by ashishc1403
0

Heya mate!!!

here is your equation:

(3 - √3)^2

= (3 - √3) (3 - √3)

= using identity ; (a - b)^2 = a^2 - 2ab + b^2

= 3^2  - 2 * 3 *√3 + √3^2

= 9 - 2 * 3^{\frac{3}{2}}  + 3

= 12 - 2 * 3^{\frac{3}{2}}

= therefore its irrational

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