Prove that 3 - root 5 is an irrational number
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Answer:
Letus assume that 3 + √5 is a rational number. This shows (a-3b)/b is a rational number. But we know that √5 is an irrational number, it is contradictsour to our assumption.
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Step-by-step explanation:
3 + √5 = a/b
we get,
=>√5 = a/b – 3
=>√5 = (a-3b)/b
=>√5 = (a-3b)/b
This shows (a-3b)/b is a rational number.
But we know that √5 is an irrational number, it is contradictsour to our assumption.
Our assumption 3 + √5 is a rational number is incorrect.
3 + √5 is an irrational number
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