Prove that (3 –root 5 ) is an irrational number.
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But we know that √5 is an irrational number. So, {(a - 3b)/b} should also be an irrational number. Hence, it is a contradiction to our assumption. Thus, 3 + √5 is an irrational number.
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Any operations with an irrational number is always irrational, therefore 3-root5 is an irrational number
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