Question

prove that 3 root 6 is an irrational number

Answer 1

let 3√6 be a rational number
3√6 =p/q [p, q€z q not equal to 0 ]
√6=p/3q
= p/3q is rational so as √6
But √6 is irrational so this contradicts our assumption. Hence, 3√6 is irrational number