Question

prove that 3+root 7 is an irrational number .....plz help its urgent ...

Answer 1

Hello friend

here's your answer

let us assume 3+√7 to be a rational number

all the rational numbers can be expressed in p/q form

So 3+√7=p/q

where p,q are integers

√7=(p/q)-3

√7=p-3q/q

As p,q are integers RHS is an irrational number

So LHS i.e √7 will be rational

But this contradicts the fact that √7 is an irrational number

This contradiction arise because of our false assumption

Therefore 3+√7 is an irrational number

Hope it helps!

Answer 2

hope it will help..............