Question

prove that 3 sin π\6 sec π\3 - 4 sin 5π\6 cot π\4​

Answer 1

Answer:

1

Explaination:

$3 \sin(\pi \div 6) \sec(\pi \div 3) - 4 \sin(5\pi \div 6) \cot(\pi \div 4) \\ 3(1 \div 2)(2) - 4 \sin(\pi - \pi \div 6) (1) \\ 3 - 4 \sin(\pi \div 6) \\ 3 - 4(1 \div 2) \\ 3 - 2 \\ 1 \: n \\ answer$

Answer 2

Answer:

1

Step-by-step explanation:

{3sin(π÷6)sec(π÷3)} - {4sin(5π÷6)cot(π÷4)}= 1

Using (π÷6)=(1÷2); (π÷4)=(1)

{(3×2)÷2} -{4sin(π-π÷6)(1)}= 1

3-4sin(π÷6)= 1

3-(4÷2)= 1

3-2= 1

1=1

Hence proved.