prove that 3 + under root 5 is an irrational number
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Let us assume that 3 + √5 is a rational number.
Now,
3 + √5 = a/b ( here a and b are co primes)
√5 = (a/b)-3
= a - 3b/b
Here, a - 3b/b is a rational number.
But we know that √5 is an irrational number.
So, a - 3b/b is also an irrational number.
Therefore, our assumption is wrong!
3 + √5 is an irrational number.
Hence, proved
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