Question

prove that 33! is divisible by 2^15. what is the largest integer n such that 33! is divisible by 2^n?​

Answer 1

Answer:

Step-by-step explanation:

So , the product of 2 present in these numbers = 2 × 2 × 2 2 × 2 × 2 × 2 2 × 2 × 2 3 × 2 × 2 2 × 2 = 2 16 Therefore , we have 2 15 × 2 16 = 2 31 Thus , 31 is the largest integer such that 33 ! is divisible by 2 n

Answer 2

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