Question

Prove that : 3cosec2

60°

-2cot30°

+sec2

45°

=0​

Answer 1

Answer:

$3 \csc(120) - 2 \cot(30) + \sec(90) \\ \\ = 3 \csc(90 + 30) - 2 \times \sqrt{3} + \infty \\ \\ = 3 \sec(30) - 2 \sqrt{3} \\ \\ = 3 \times \frac{2}{ \sqrt{3} } - 2 \sqrt{3} \\ \\ = \frac{6}{ \sqrt{3} } - 2 \sqrt{3} \\ \\ = \frac{6 - 2 \sqrt{3} \sqrt{3} }{ \sqrt{3} } \\ \\ = \frac{6 - 6}{ \sqrt{3} } \\ \\ = \frac{0}{ \sqrt{3} } \\ \\ = 0 \\ \\ = rhs \\ \\ hence \: proved$

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Answer 2

Answer:

=3*4/3-2*3+2

=4-2*3+2

=0

I think the question typed by you is incorrect

There should be -cot²30 not -2cot30

But i have given solution according to my understanding of question