Question

Prove that 3cosec²60° - 2cot²30° + sec²45° = 0​

Answer 1

Answer:

Here is ur answer

Step-by-step explanation:

3cosec260∘−2cot230∘+sec245∘=0

L.H.S. = 3cosec260∘−2cot230∘+sec245∘

= 3(32)2−2(3)2+(2)2

= 3(34)−2(3)+2

= 4−6+2

= 0

Answer 2

Answer:

Prove that 3cosec²60° - 2cot²30° + sec²45° = 0

Step-by-step explanation:

Sum:

LHS

=3cosec²60° - 2cot²30° + sec²45°

=3(2/√3)^2-2(√3)^2+(√2)^2

=3×4/3-2×3+2

=4-6+2

=0

=RHS

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