Prove that √3is irrational number.
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let √3 be a rational no.
√3=p/q
on squaring both the sides
3 = p²/q²
p²=3q²
p² is divisible by 3
p is also divisible by 3...................1
let p=3k
on squaring both the sides we get
p² = 9k²
From above p² = 3q²
3q² = 9k²
q² = 3k²
q² is divisible by 3
q is also divisible by 3..................2
from 1 & 2 p&q both are divisible by 3
So this contradicts that √3 is a rational no.
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