Question

prove that 3log7-2log5=log345/25​

Answer 1

Step-by-step explanation:

$3 log(7) - 2 log(5) = log\frac{343}{25} \\ lhs \: \: \: \: \\ = log( {7}^{3} ) - log( {5}^{2} ) \\ log( \frac{343}{25} ) = log( \frac{343}{25} )$

proved

i hope its helpfull

Answer 2

→3log7 - 2log5

→ log7³ - log5²

→ log (7³/5²)

→ log343/25

Hence Proved

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