Question

Prove that 3root5 -8 is irrational

Answer 1

Step-by-step explanation:

let3√5-8=a/b,

where a and b are integers

now,

3√5-8=a/b

3√5=a/b+8

3√5=a+8b/b

√5=a+8b/3b

therefore the above two sides that is lhs and rhs are rational.

But this contradicts the fact that√5 is rational is irrational number .

therefore our assumption is wrong.

Therefore 3√5-8 is irrational number

Answer 2

Step-by-step explanation:

see the pic attached

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