prove that 3x-4y+5=0,x+2y=3,3x-4y+15=0,x+2y=9 are lines of a parallelogram
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Step-by-step explanation:
Given equations of lines are
3x−4y+1=0,3x−4y+3=0,4x−3y−1=0 and 4x−3y−2=0,
Here m
1
=
4
3
,m
2
=
3
4
and c
1
=
4
1
,c
2
=
4
3
,d
1
=−
3
1
,d
2
=−
3
2
Area of parallelogram =
∣
∣
∣
∣
∣
m
1
−m
2
(c
1
−c
2
)(d
1
−d
2
)
∣
∣
∣
∣
∣
=
7
2
sq.units
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