Question

prove that (3x+7) is a factor of p(X)=6x^3-29x^2+44x+21​

Answer 1

Answer:

3x+7=0

3x=0-7

3x=-7

x=-7/3

put x =-7/3

p(x)=6(-7/3)^3-29(-7/3)^2+44(-7/3)+21

Answer 2

Answer:

Here p(x) = the dividend polynomial = 6x3 + 29x2 + 44x + 21

s(x) = the divisor polynomial = 3x + 7

Now,

∴ The quotient polynomial q(x) = 3x + 7 and the remainder polynomial r(x) = 0.

∴ The other polynomial is 2x2 + 5x + 3

Step-by-step explanation: