Prove that 4-3√2 is an irrational.
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Step-by-step explanation:
let, the 4-3√2 is rational number and written in the form of P/q ,
i.e, 4-3√2 = P/q
-3√2 = P/q - 4
-3√2 = (P - 4q) / q
√2. = (P - 4q ) / -3q
irrational =/= rational
hence, 4-3√2 is an irrational number.
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