prove that (4,3) (6,4) (5,6) and (3,5) are the vertices of a square
Answers
Answered by
0
Answer:
ANSWER
Let A(4,3),B(6,4),C(5,6),D(3,5)
So by distance formula we have,
Distance between two points =
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
AB=
(4−6)
2
+(3−4)
2
=
5
BC=
(6−5)
2
+(4−6)
2
=
5
CD=
(5−3)
2
+(6−5)
2
=
5
DA=
(3−4)
2
+(5−3)
2
=
5
AC=
(5−4)
2
+(6−3)
2
=
10
BD=
(6−3)
2
+(4−5)
2
=
10
All sides are equal and diagnols are equal , the given points are angular
points of a square
Similar questions