prove that 4/√3 is an irrational number
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Answer:
Step-by-step explanation:
Let us assume the contrary, that 4−
3
is rational.
That is, we can find co-prime a and b (b
=0) such that 4−
3
=
b
a
.
Therefore 4−
b
a
=
3
.
Rearranging this equation, we get
3
=4−
b
a
=
b
4b−a
Since a and b are integers, we get
b
4b−a
is rational, and so
3
is rational.
But this contradicts the fact that
3
is irrational,
This contradicts the fact that
3
is irrational.
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