Prove that 4-5 root 2 is an irrational no.
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Answered by
40
let (4-5√2) be a rational number.
so,
(4-5√2) = p/q.
√2 = 4q-p/5q ,which is a rational number
but √2 is an irrational number
so, 4-5√2 is an irrational number...
so,
(4-5√2) = p/q.
√2 = 4q-p/5q ,which is a rational number
but √2 is an irrational number
so, 4-5√2 is an irrational number...
Answered by
23
Consider, 4−5√2
Let 4−5√2 = (a/b) a rational number
⇒ −5√2 = (a/b) − 4
⇒ −5√2 = (a − 4b)/b
⇒ √2 = (a − 4b)/(−5b)
Since a, b are integers, then (a − 4b)/(−5b) represents a rational number.
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