Prove that
4(cos³10°+sin³20°) = 3(cos10°+sin20°)
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Step-by-step explanation:
cos 3θ = 4cos^3 θ - 3cosθ
=> 4cos^3 θ = cos3θ + 3 cosθ
Taking θ = 10°
=> 4cos^3 10° = cos30° + 3cos10° ... ( 1 )
sin3θ = 3sinθ - 4sin^3 θ
=> 4sin^3 θ = 3sinθ - sin3θ
Taking θ = 20°
=> 4sin^3 20° = 3sin20° - sin60° ... ( 2 )
Adding ( 1 ) and ( 2 ),
4(cos^3 10° + sin^3 20°) = 3(cos10° + sin20°) + cos30° - sin60°
=> 4(cos^3 10° + sin^3 20°) = 3(cos10° + sin20°) ... [because cos30° = sin60°]
Edit:
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