Prove that 4^n does not end with zero ,where n is a natural number
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4¹ = 4
4² = 16
4³ = 64
4⁴ = 256
Hence, every odd power of 4 ends with 4 and even power ends with 6.
Hence, 4ⁿ does not end with 0 for all n∈ N
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- any number which can be converted in 2 x 5 form and with 0
- as 4 cannot be converted in form 2x 5 it will not end with zerp
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