prove that 45n cannot end with a zero.
(Maths)
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Step-by-step explanation:
For a digit to end with 0 it should have both 2 and 5 as a factor. It only has 5 as a factor and 2 is missing. Hence any number of the form 45^n (where n is any natural number) cannot end with the digit zero
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Answer:
the count of zero is u०00 1co arw yj the systerm of computer come the she fbn from getting day
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