Prove That √49 Is Irrational Number
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Answer:bro it's not √49 = 7 that is rational
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Step-by-step explanation:
let √49 be a rational no.
such that √49 = p/q
where p and q do not have any common factors and q is not equal to 0
squarring on both sides,
49=p^2/q^2
p^2= 49q^2
therefore 49 is a factor of p^2 and 49 is a factor of p -(1)
let p be any unknown no.
p=49m
Substitute value of p
(49m)^2=49q^2
2401m^2= 49q^2
q^2=2401m^2/49
q^2=49m^2
therefore 49 is a factor of q^2
49 is a factor of q-(2)
from 1 and 2
49 is a factor of both p and q
but by the rule stated ,, this is not possible ,
hence √49 is not rational
it is irrational
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